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試験番号：1z1-061 試験問題集
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NO.1 Select three valid statements related to the Shared Service Model.
A. Shared Service Personnel can view Invoices across various business units.
B. Shared Service Personnel can do cross-business unit cash application.
C. Shared Service Personnel can process invoices for various business units.
D. Shared Service Personnel can see customer account details across business units.
E. Shared Service Personnel can report data across all business units but can enter transactions
ONLY against one business unit.
Answer: A,C,E

Oracle 科目   1z0-506 参考書   1z0-506   1z0-506

NO.2 Select three values that default from Customer Profile Classes.
A. Currency
B. Legal Entity
C. Payment Terms
D. Statement Cycle
E. Business Purpose
Answer: A,C,D

Oracle 模擬   1z0-506 対策   1z0-506 攻略

NO.3 You have created an Invoice with an incorrect unit price. You need to perform the Rebill task
from
the Manage Transactions user interface to enter the correct transaction. Which two actions does
the Manage Transactions user interface allow you to perform for the Rebill task?
A. Duplicate the original transaction.
B. Create a credit memo.
C. Incomplete the transaction.
D. Reverse the Transaction.
E. Correct the unit price.
Answer: A,B

Oracle 一発合格   1z0-506   1z0-506 フリーク   1z0-506 認定資格   1z0-506 問題集

NO.4 The drilldown option available in the task pane for receipts does NOT include ____________.
A. Create Remittance via Spreadsheet
B. Correct Funds Transfer Errors
C. Lockbox Transmission History
D. Create Receipt via Spreadsheet
Answer: C

Oracle 認証試験   1z0-506 科目   1z0-506   1z0-506   1z0-506 問題集
6. You can click the manager Invoice Lines from the Billing Work Area to find Autoinvoice
Exceptions. What parameters are used to summarize the exceptions for review?
A. Business Unit, Transaction Type, Invoice Date, Currency
B. Business Unit, Customer Name, Transaction Source, Total Amount
C. Business Unit, Transaction Source, Creation Date, Currency
D. Business Unit, Transaction Source, Transaction Type, Creation Date
Answer: D

Oracle 難易度   1z0-506 練習   1z0-506   1z0-506 日記   1z0-506 日記   1z0-506 認定資格
7. Which functionality is NOT provided by the Receivables to Ledger Reconciliation Report?
A. Limiting the display using the ad hoc parameter
B. Drilldown to see reconciling details
C. Drilldown to see what needs to transfer and post to the general ledger
D. Graphical and visualization components for viewing the reconciliation details
E. The reasons for the reconciling differences
Answer: C

Oracle   1z0-506 スクール   1z0-506   1z0-506 模擬
8. A customer calls into the Accounts Receivables Department asking for the balance of all
invoices
due in the next 30 days and has a question about a specific invoice line. As a Billing Specialist
what action will you perform?
A. Review the invoice in the Review Customer Account Details user interface.
B. Apply, reverse, or process the receipt.
C. Create an open debit memo.
D. Review receipt-, in pending status
Answer: A

Oracle 合格率   1z0-506 問題   1z0-506 ガイド
9. The billing Specialist creates an adjustment for an INCORRECT invoice and sends it for approval
through the review and Manage Transaction link in the Billing Work Area. Since the adjustment
amount is above approval limit, it is routed to the Billing Manager. What is the status of the
Adjustment when the approver sees the adjustment in his Work Queue?
A. Pending Research
B. Pending Approval
C. Approval Required
D. Waiting Approval
Answer: D

Oracle 学校   1z0-506 PDF   1z0-506 認証試験   1z0-506 認定
10. You are the Billing Manager and you are in charge of reviewing transactions and approving
them.
Which two tabs are available for your role in the Adjustments Overview Region on the Billing Work
Area page?
A. Pending My Approval
B. Pending Approval
C. Pending Approval from Others
D. Approved
E. Pending Research
Answer: B,C

Oracle 短期   1z0-506   1z0-506 取得   1z0-506 入門

NO.5 The collections Manager runs the Determine Delinquency Using Scoring program to identify
delinquent transitions. She wants to know the status of a particular transaction. On which tab she
will find the status.
A. Customer Aging tab
B. Transaction Details tab
C. Transactions tab
D. Transaction aging tab
Answer: C

Oracle 科目   1z0-506   1z0-506 認定

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試験番号：1z0-481問題集
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試験番号：1z1-061問題集
試験科目：Oracle 「Oracle Database 12c: SQL Fundamentals」
問題と解答：全75問

試験番号：1z0-061問題集
試験科目：Oracle 「Oracle Database 12c: SQL Fundamentals」
問題と解答：全75問

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NO.1 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c
Answer: C

Oracle過去問   1z1-061認定証   1z1-061

NO.2 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It produces an error because the AMT_SPENT column contains a null value.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: C

Oracle   1z1-061認定試験   1z1-061認定試験   1z1-061
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.

NO.3 Examine the structure proposed for the transactions table:
Which two statements are true regarding the creation and storage of data in the above table
structure?
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The CUST_STATUS column would store exactly one character.
D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
E. The TRANS_VALIDITY column would have a maximum size of one character.
F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes,
seconds, and fractions of seconds
Answer: B,C

Oracle認定資格   1z1-061認定試験   1z1-061
Explanation:
VARCHAR2(size)Variable-length character data (A maximum size must be specified:
minimum size is 1; maximum size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p, s)] Number having precision p and scale s (Precision is the total number of
decimal digits and scale is the number of digits to the right of the decimal point; precision
can range from 1 to 38, and scale can range from -84 to 127.)
DATE Date and time values to the nearest second between January 1, 4712 B.C., and
December 31, 9999 A.D.

NO.4 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
D. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
Answer: D

Oracle認定資格   1z1-061認定試験   1z1-061

NO.5 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. JOIN; JOIN
B. FULL OUTER JOIN; FULL OUTER JOIN
C. RIGHT OUTER JOIN; LEFT OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: C

Oracle   1z1-061認定証   1z1-061

NO.6 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. Abigail PA
B. Abigail Pa
C. Abigail IS
D. An error message
Answer: B

Oracle   1z1-061   1z1-061   1z1-061

NO.7 You need to create a table for a banking application. One of the columns in the table has the
following requirements:
1. You want a column in the table to store the duration of the credit period.
2) The data in the column should be stored in a format such that it can be easily added and
subtracted with date data type without using conversion functions.
3) The maximum period of the credit provision in the application is 30 days.
4) The interest has to be calculated for the number of days an individual has taken a credit for.
Which data type would you use for such a column in the table?
A. DATE
B. NUMBER
C. TIMESTAMP
D. INTERVAL DAY TO SECOND
E. INTERVAL YEAR TO MONTH
Answer: D

Oracle認定資格   1z1-061問題集   1z1-061認証試験   1z1-061認定試験

NO.8 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 1 executes successfully and gives the required result.
B. Only statement 2 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D

Oracle   1z1-061問題集   1z1-061参考書   1z1-061

NO.9 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. First normal form
B. Second normal form
C. Third normal form
D. Fourth normal form
Answer: B

Oracle   1z1-061   1z1-061認証試験   1z1-061練習問題   1z1-061認定資格

NO.10 Which three tasks can be performed using SQL functions built into Oracle Database?
A. Displaying a date in a nondefault format
B. Finding the number of characters in an expression
C. Substituting a character string in a text expression with a specified string
D. Combining more than two columns or expressions into a single column in the output
Answer: A,B,C

Oracle   1z1-061問題集   1z1-061   1z1-061認定証   1z1-061認証試験

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試験番号：1z1-061問題集
試験科目：Oracle 「Oracle Database 12c: SQL Fundamentals」
問題と解答：全75問

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NO.1 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It produces an error because the AMT_SPENT column contains a null value.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: C

Oracle   1z1-061問題集   1z1-061
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.

NO.2 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. Abigail PA
B. Abigail Pa
C. Abigail IS
D. An error message
Answer: B

Oracle   1z1-061   1z1-061   1z1-061

NO.3 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
D. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
Answer: D

Oracle   1z1-061   1z1-061   1z1-061過去問   1z1-061認定資格   1z1-061

NO.4 You need to create a table for a banking application. One of the columns in the table has the
following requirements:
1. You want a column in the table to store the duration of the credit period.
2) The data in the column should be stored in a format such that it can be easily added and
subtracted with date data type without using conversion functions.
3) The maximum period of the credit provision in the application is 30 days.
4) The interest has to be calculated for the number of days an individual has taken a credit for.
Which data type would you use for such a column in the table?
A. DATE
B. NUMBER
C. TIMESTAMP
D. INTERVAL DAY TO SECOND
E. INTERVAL YEAR TO MONTH
Answer: D

Oracle過去問   1z1-061認定証   1z1-061参考書   1z1-061認定試験   1z1-061認定試験

NO.5 Examine the structure proposed for the transactions table:
Which two statements are true regarding the creation and storage of data in the above table
structure?
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The CUST_STATUS column would store exactly one character.
D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
E. The TRANS_VALIDITY column would have a maximum size of one character.
F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes,
seconds, and fractions of seconds
Answer: B,C

Oracle   1z1-061   1z1-061   1z1-061
Explanation:
VARCHAR2(size)Variable-length character data (A maximum size must be specified:
minimum size is 1; maximum size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p, s)] Number having precision p and scale s (Precision is the total number of
decimal digits and scale is the number of digits to the right of the decimal point; precision
can range from 1 to 38, and scale can range from -84 to 127.)
DATE Date and time values to the nearest second between January 1, 4712 B.C., and
December 31, 9999 A.D.

NO.6 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c
Answer: C

Oracle   1z1-061認定資格   1z1-061過去問   1z1-061

NO.7 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 1 executes successfully and gives the required result.
B. Only statement 2 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D

Oracle   1z1-061練習問題   1z1-061認定試験   1z1-061認定試験

NO.8 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. JOIN; JOIN
B. FULL OUTER JOIN; FULL OUTER JOIN
C. RIGHT OUTER JOIN; LEFT OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: C

Oracle   1z1-061練習問題   1z1-061参考書

NO.9 Which three tasks can be performed using SQL functions built into Oracle Database?
A. Displaying a date in a nondefault format
B. Finding the number of characters in an expression
C. Substituting a character string in a text expression with a specified string
D. Combining more than two columns or expressions into a single column in the output
Answer: A,B,C

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NO.10 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. First normal form
B. Second normal form
C. Third normal form
D. Fourth normal form
Answer: B

Oracle認定試験   1z1-061認定資格   1z1-061練習問題   1z1-061

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